Write a function that returns the number of repetition of a character in a string
You should not use ready -made functions for this question
count_char("hooshang", "o") #2
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```def duplicate_string(string,char):
"""
این تابع برای نشان دادن تعداد حروف تکراری
در یک استرینگ است
"""
# Wear the variable value zero and the desired string with the circle
count = 0
for i in string :
if i == char: # If the characters in the navigation were one with our second entrance
count += 1 # Add one number to Kant
return count # Print out the output
# Frequently function and give two inputs to the function
filter_char = duplicate_string("mohammad","m")
print(filter_char)```
Python
function count_1(s, c) {
let count = 0;
for (let char in s) {
if (char === c) {
count += 1;
}
}
return count;
}
const result = count_1("h", "o");
console.log(result);
JavaScript
def count_char(txt,char):
count=0
for i in t:
if c==i:
count+=1
print(count if count>0 else 'nout found')
t=input('enter your text: ')
c=input('enter your char: ')
count_char(t,c)
Python
def string_txt(s):
my_text = {}
for item in s:
if item in my_text:
my_text[item] += 1
else:
my_text[item] = 1
return my_text
Python
def chek_try_str(string,char):
return string.count(char)
text=input('input one string:')
char=input('input char for count:')
print(f"the character appears'{char}',{chek_try_str(text,char)} times in the string.")
Python
def count(x,y):
l=[]
for i in x:
l.append(i)
l2=filter(lambda x : True if x==y else False , l)
return len(list(l2))
print(count('hooshang',"o")) #2
Python
# Number
def count_char(string, char):
return string.count(char)
print(count_char("hooshang", "o"))
Python
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