Detect the full number

def Perfect_Number(number):
    total_number=0
    if number<1:
        return False
    for num in range(1,number):
        if number % num ==0:
            total_number+=num
    return total_number==number
number_input=int(input("inter number: "))       
print(Perfect_Number(number_input))

User 943

9

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num = input("Enter your number: ")
print(True) if sum([i for i in range(1, int(num)) if int(num) % i == 0]) == int(num) else print(False)

User 111

1

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try:
        num=int(input("number: "))
    except:
        exit()
    i=num-1
    mode_list=[]
    while i>0:
        if(num%i==0):
            mode_list.append(i)
        i-=1
    sum=0
    for item in mode_list:
        sum+=item
    if(sum==num):
        print("Kamel")
    else:
        print("Kamel Nist")

Saeeda33

S

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n=int(input('number:'))
a=0
for i in range(1,n):
    if n%i==0:
        a=a+i
    else:
        pass
print(a==n)

Meysam.derakhshan

M

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# The program that checks whether a complete number is
def is_perfect_number(n):
    # Calculate the sum of the amount of the amount against the number (except the number itself)
    divisors_sum = sum(i for i in range(1, n) if n % i == 0)
    
    # Check whether the sum of the amount of the amount against the identity is equal to the number itself
    return divisors_sum == n

# Get a number from the user
number = int(input("یک عدد وارد کنید: "))

# Review and display the result
if is_perfect_number(number):
    print(f"{number} یک عدد کامل است.")
else:
    print(f"{number} یک عدد کامل نیست.")

Milad.bio

M

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while True :
    number = int(input("adad morede nazar ra vared konid :  "))
    r = list(range(1,number))
    l = []
    
    for x in r :
        if number % x == 0 :
            l.append(x)
        if sum(l) == number :
            print(l)
            break
    else :
        print("in adad kamel nist , lotfan adade digar vared konid")

Emrimo

E

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