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Numbers to power 2

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Write a program that receives a number from the input and increases the number 2 and prints in the output. This trend continues until the number 0 is not arrived

11 Answers

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let msg = 'error'
alert(msg) 
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let msg = 'error'
alert(msg) 
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This answer is only visible to premium members
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let msg = 'error'
alert(msg) 
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while 1:
	number=float(input("enter  numbers:"))
	a=number**2
	if number !=0:
		print(a)
	else:
		break 
		print("end")
Roghaye.m Download Python
def main():
    while True:
        # Get a number from the user
        number = float(input("لطفاً یک عدد وارد کنید (برای خروج 0 را وارد کنید): "))
        
        # Check out of the loop
        if number == 0:
            print("برنامه به پایان رسید.")
            break
        
        # Calculating and printing power of 2 pcs
        squared = number ** 2
        print(f"{number} به توان 2 برابر است با: {squared}")

# Implementation of the program
main()
Mma123 Download Python
while 1:
    number = int(input("enter num: "))
    
    if number != 0:
        power = number ** 2
        print(power)
    else:
        break
print("end")
number = 1
while True:
    try:
        if not  number == 0:
            number = int(input("enter your number:"))
            print(f"your number:{number ** 2}")
        else:
            break
    except:
        print("eror")
Mohamad Download Python
while 1:
    number = int(input("please enter a number: "))
    if number == 0:
        break
    else:
        print("number ** 2 = ", number ** 2)
number = int(input("enter your number:"))
tavvan = number ** 2
if number == 0:
    print("end")
else:
    print(tavvan)
def print_nums_power_of_two(n):
    while n == 0:
        print("Because the number zero reaches the power of two, the result is zero, the program closes!!")
        break
    else:
        print(f"The number {n} to the power of two {n ** 2} is.")
        print_nums_power_of_two(int(input("Enter a number: ")))
print_nums_power_of_two(int(input("Enter a number: ")))
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