Write a program to format to format yyyy/mm/dDReceive from the user and check whether the date received in the correct format is correct.
Example:
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import jdatetime
year = int(input("entry your year:"))
month = int(input("enter your month:"))
day = int(input("entter your day:"))
x = jdatetime.date.fromgregorian(year = year , month = month , day = day)
print(x)
date1 = jdatetime.date.today()
print(date1)
if x == date1:
print(True)
if x != date1:
print(False)
Python
year = int(input("entry your year:"))
month = int(input("enter your month:"))
day = int(input("entter your day:"))
print(f"{year}:{month}:{day}")
if month > int(12) and day > int(31):
print("tarikh dar fomat eshtebah ast")
else:
print("tarikh dar format dorosh ast")
import re
from datetime import datetime
def is_valid_date(date_string):
# Review of date format using Regex
pattern = r'^\d{4}/\d{2}/\d{2}$'
if not re.match(pattern, date_string):
return False
# Convert the history of history to the Datetime object and examine the accuracy of history
try:
year, month, day = map(int, date_string.split('/'))
datetime(year, month, day)
return True
except ValueError:
return False
def main():
date_input = input("تاریخ را به فرمت yyyy/mm/dd وارد کنید: ")
is_valid = is_valid_date(date_input)
print(is_valid)
if __name__ == "__main__":
main()
Python
user_date = input("Please enter date: (format: yyyy/mm/dd)")
lst_date = user_date.split("/")
if 0 < int(lst_date[1]) <= 12 and 0 < int(lst_date[2]) <= 31:
print(True)
else:
print(False)
Python
from datetime import datetime
user_date = input("Please enter date: (format: yyyy/mm/dd)")
try:
datetime.strptime(user_date, "%Y/%m/%d")
print (True)
except :
print (False)
Python
year = int(input("year: "))
month = int(input("month: "))
day = int(input("day: "))
format_ymd = f"{year}/{month}/{day}"
if year > 2025:
print(f"History : {format_ymd} year error")
print("False")
elif month > 12:
print(f"History : {format_ymd} month error")
print("False")
elif month > 30:
print(f"History : {format_ymd} day error")
print("False")
elif year < 2025 and month < 13 and day < 31:
print(f"History : {format_ymd}")
print("True")
else:
print("Not")
Python
The format (yyyy/mm/dd) is controlled by the moon and day.
#include <iostream>
using namespace std ;
int main() {
string date ;
cout << "Enter date (yyyy/mm/dd) : " ;
cin >> date ;
string y = date.substr(0,4);
string m = date.substr(5,2);
string d = date.substr(8,4);
int year = stoi(y);
int month = stoi(m);
int day = stoi(d);
bool flag ;
if (y.length() == 4 && m.length() == 2 && d.length() == 2) {
flag = true ;
}
if (flag && 0 < month <= 6 && 0 < day <= 31 ) {
cout << "True" << endl;
} else if (flag && 6 < month <= 12 && 0 < day <= 30) {
cout << "True" << endl;
} else {
cout << "False" << endl;
}
return 0;
}
C & C++
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