The segmentability of the two numbers
Write a program that receives two A and B numbers from the user and checks whether the number A by B is segmentable.
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Write a program that receives two A and B numbers from the user and checks whether the number A by B is segmentable.
let msg = 'error' alert(msg)This answer is only visible to premium members
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This answer is only visible to premium members
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a = int(input("number1:"))
y = int(input("number2:"))
if y > a:
e = y % a
if e == 0:
print("True")
else:
print("False")
else:
e = a % y
if e == 0:
print("True")
else:
print("False")
Python
while True:
a = int(input("enter a number: "))
b = int(input("enter a number2:(b!=0) "))
if a % b == 0:
print("yes")
else:
print("No")
while 1:
a = int(input("number 1 : "))
b = int(input("number 2 : "))
if b != 0:
if a % b == 0:
print("bakhshpazir ast")
else:
print("bakhshpazir nist")
else:
print(" number 2 can't be (0)")
Python
def bakhsh_paziri():
a = float(input("Enter the first number: "))
b = float(input("Enter the second number: "))
if a//b == 0:
return True
else:
return False
print(bakhsh_paziri())
Python
a=int(input("a:"))
b=int(input('b:'))
print(a%b==0)
Python
a = int(input("enter your number:"))
b = int(input("enter your number:"))
if a % b == 0:
print(True)
else:
print(False)
Python
a=int(input("Enter a number: "))
b=int(input("Enter a number: "))
c=(a%b)
if c==0:
print("True")
Python
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