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Countdown timer

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Write a program that receives a number and from that number to 0 countdown

Between each number of 1 second pause is required

12 Answers

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let msg = 'error'
alert(msg) 
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let msg = 'error'
alert(msg) 
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This answer is only visible to premium members
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let msg = 'error'
alert(msg) 
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import time
l = []
n = int(input("Enter: "))
for i in range(n):
    l.append(i)
l.append(n)
l.reverse()
for i in l:
    print(i)
    time.sleep(1)
Roham Download Python
from time import sleep
def print_countdown(number):
    while number >= 0:
        print(number)
        sleep(1)
        number -= 1
        if number == -1:
            break
print_countdown(number = int(input("Enter a number: ")))
Zehsanz274 Download Python
import time
num = int (input ('Enter a number: '))
for i in range (num,-1,-1):
    time.sleep(1)
    print (i)
import time

# Get a number from the user
number = int(input("لطفاً یک عدد وارد کنید: "))

# Countdown
for i in range(number, -1, -1):
    print(i)
    time.sleep(1)  # Pause 1 second
User 136 Download Python
import time
def countdown(number):
    """Countdown from the given number to 0 with a 1-second delay."""
    for i in range(number, -1, -1):
        print(i)
        time.sleep(1)
# Get input from the user
try:
    number = int(input("یک عدد وارد کنید: "))
    countdown(number)
except ValueError:
    print("لطفاً یک عدد صحیح وارد کنید.")
Milad.bio Download Python
import time
number = int(input("please enter a number: "))
while 0 <= number:
    print(number)
    number -= 1
    time.sleep(1)
# Import Libraries
import time

# Constructing ridicules and receiving time
Time = int(input('please enter time(sec) : '))
x = Time

# Start the countdown
for i in range(Time) :
    if x != 1 :
        print(x)
        time.sleep(1)
        x -= 1
    else :
        print(x)
        break
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