Printing numbers 1 to 2
Write a program that print numbers 1 to 2 in the output
Write a program that print numbers 1 to 2 in the output
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let msg = 'error' alert(msg)This answer is only visible to premium members
This answer is only visible to premium members
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public class chap_yek_ta_sad { public static void main(String[] args) { for(int i = 1;i<=100;i++){ System.out.println(i); } } }
w = 1 while True: if w > 100: break else: print(w) w += 1
new = [] for i in range(1,101): new.append(i) else: print(new)
def a(m): print(m) if m == 1: return 1 return a(m-1) a(100)
for i in range(1,100): print(i)
print([ i for i in range(1,101)])
def print_numbers(start, end): lst_nums = [] while start <= end: lst_nums.append(start) start += 1 yield lst_nums print(f"List of numbers from 1 to 100: {next(print_numbers(1, 100))}")
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Write a function that returns the number of a character in a string. To this question you should not use ready -to -use functions ("hooshang", "O") #2
Write a function that receives infinite parameter and returns the average of numbers. If the parameter was non -extensive, it ignores it
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