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The shape of descending numbers

Practice Easy 21/ Download 2106 Views

Write a program that receives a number and prints the figure below according to the number received

Example:

number: 5
55555
4444
333
22
1 

11 Answers

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let msg = 'error'
alert(msg) 
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let msg = 'error'
alert(msg) 
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let msg = 'error'
alert(msg) 
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def print_pattern(n):
    for i in range(n, 0, -1):
        print(str(i) * i)

def main():
    try:
        number = int(input("عدد را وارد کنید: "))
        if number < 1:
            print("لطفاً عددی بزرگتر از صفر وارد کنید.")
            return
        print_pattern(number)
    except ValueError:
        print("لطفاً یک عدد صحیح وارد کنید.")

if __name__ == "__main__":
    main()
User 136 Download Python
num = int(input("enter num: "))     
while num > 0:
    print(num * str(num))
    num-=1
a=input("number:")
b=int(a)
for i in range (1 , b+1) :
    print(a*b)
    a=int(a)
    a=a-1
    a=str(a)
    b=b-1
Parsa.r Download Python
UserNumber=input('enter a an integer number= ')
while int(UserNumber)==0:
    print("enter another number")
    UserNumber = input('enter a an integer number= ')
def PosetiveNumber(UserNumber):
    while int(UserNumber) != 0:
        print(int(UserNumber) * str(UserNumber))
        UserNumber = str(int(UserNumber) - 1)
def NegetiveNumber(UserNumber):
    while int(UserNumber) != 0:
        print((int(UserNumber) * -1) * str(UserNumber))
        UserNumber = str(int(UserNumber) + 1)

while int(UserNumber!=0):
    if int(UserNumber)>0:
        PosetiveNumber(UserNumber)
    else:
        NegetiveNumber(UserNumber)
    answer=input('do you want to try another number ? ').lower()
    if answer=='yes':
        UserNumber = input('enter a an integer number= ')
        while int(UserNumber) == 0:
            print("enter another number")
            UserNumber = input('enter a an integer number= ')
    else:
        print('-----END-----')
        break
User 703 Download Python
n = int(input())
for i in range(n , 0 , -1) :
    print(i * str(i))

Arshia.a Download Python
def countdown(number):
    while number > 0:
        counter = str(number)
        print(counter*number)
        number -= 1
try:
    number = int(input('number: '))
    countdown(number)
except ValueError:
    print('please inter a natural number')
x = int(input("Enter a number: "))
while x < 1:
    print("Please enter a number greater than zero")
    break
for a in range(x, 0, -1):
    print(str(a)*a)
Ali.r.h.z Download Python
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