Converting number to binary (zero and one)
Write a function that aThe number to binaryOr oneBinary string to numberTurn
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Write a function that aThe number to binaryOr oneBinary string to numberTurn
let msg = 'error' alert(msg)This answer is only visible to premium members
This answer is only visible to premium members
let msg = 'error' alert(msg)This answer is only visible to premium members
This answer is only visible to premium members
let msg = 'error' alert(msg)This answer is only visible to premium members
This answer is only visible to premium members
def f(n):
if n==0:
return '0'
m=''
while n>0:
m+=str(n%2)
n=n//2
return m
n=int(input(":"))
print(f(n ))
Python
x = int(input("Enter integer number: "))
lst = []
while x>0:
c = x%2
x = x//2
lst.append(c)
st = ""
for i in lst[::-1]:
st += str(i)
print(f"binery number is {st}")
number=int(input("enter a number for I show your number in binary number :) >>>>"))
binary_number=bin(number)
print("binaried your number--->",binary_number)
def convert_number_binary(value):
if isinstance(value, int):
return bin(value)[2:]
elif isinstance(value, str):
return int(value, 2)
else:
raise ValueError("Input must be an integer or a binary string.")
#include <iostream>
#include <cmath>
using namespace std;
int q(long int x , string y){
long int b ,a;
int i ,c = 1 ,n ,s ,d = 1 ,e = 1 ,j;
b = 0;
s = 0;
a = x;
for (n = 1 ; a / 10 > 0 ; n++){
a = a / 10;
}
if (y == "b"){
for (x ; x > 0 ; x = x / 2){
b = b + (x % 2) * c;
c = c * 10;
}
return b;
}
else if (y == "o"){
for (i = 0 ; i < n ; i++){
s = s + ((x / d) % 10) * e;
d = 10;
e = 2;
for (j = 0 ; j < i ; j++){
d = d * 10;
e = e * 2;
}
}
return s;
}
else{
cout<<"eror!!! : we have only binery and number !!!";
cin>>x;
cin>>y;
q(x , y);
}
}
int main(){
long int x;
string y;
cout<<"enter the number : ";
cin>>x;
cout<<"would you like it to be binary {b} or Ordinary number {o} : ";
cin>>y;
cout<<q(x ,y);
return 0;
}
C & C++
def q(x ,y ,n):
b = 0
s = 0
c = 1
d = 1
e = 1
if y == "b":
while x > 0 :
b = b + (x % 2) * c
c = c * 10
x = x // 2
return b
elif y == "o":
for i in range(n):
s = s + ((x // d) % 10) * e
d = 10
e = 2
for j in range(i):
d = d * 10
e = e * 2
return s
else:
return "eror!!! : we have only binery and number !!!"
X = input("enter the number : ")
y = input("would you like it to be binary [b] or Ordinary number [o] : ")
n = len(X)
x = int(X)
print(q(x ,y ,n))
Python
def num_to_binary(num):
binery = bin(num)[2:]
return binery
def binary_to_num(num):
number = int(num,2)
return number
menu = int(input('1-num to binary 2-binary to num'))
if menu == 1 :
num = int(input('enter number: '))
print(num_to_binary(num))
elif menu == 2 :
num = input('enter binary: ')
print(binary_to_num(num))
Python
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